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Grenadier Standard
PLEASE help in finding the standard deviation of this question; I am desperate!!?
The lengths of sunfish in Grenadier Pond are normally distributed with a mean of 15 cm. Find the standard deviation, to one decimal place if 91% of these fish have a length less than 17.7 cm
X~N(15, s²)
phi((17.7-15)/s) = 0.91
Lookup 0.91 on the normal distribution table to find that:
(17.7-15)/s = 1.34
so s = 2.0
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| FIRST LEGION NAP0294 Austrian Hahn Grenadier Standard Bearer Painted Metal | | | US $110.62 | 19d 17h 39m |
| Frontline Figures French Horse Grenadier Standard FHG7 | | | US $68.00 | 11h 37m |
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Please, I am begging for help with this standard deviation question!!?
The lengths of sunfish in Grenadier Pond are normally distributed with a mean of 15 cm. Find the standard deviation, to one decimal place if 91% of these fish have a length less than 17.7 cm.
Your statistics text should have a chart in the back (maybe the front) that can help you with this question. The sum of the row and column numbers of the chart total z, which is the number of standard deviations away from the mean. My text has that at z ≈ 1.34, we have P(z) = 91%. (It's actually a little higher, because the percentage is actually 90.99%.)
So we have z = 1.34, or that 17.7 cm is 1.34 standard deviations above the mean, which is 15. 17.7 - 15 = 2.7, so 1.34 std. dev. = 2.7 cm. To finish finding the standard devation, then, we divide by 1.34: the standard devation is 2.014925... cm, or about 2.0 centimeters.
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